First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Answer:
A) 
B) 14 gallons of gasoline
<span> s = -16t^2 + 64t + 3
v = -32t + 64
the maximum height occurs when v = 0:
-32t + 64 = 0 when t = 2 sec
the maximum height is
s = -16(2^2) + 64(2) + 3 = 67 ft
the range is [ 3, 67] </span>
Answer:
b = -36
Step-by-step explanation:
Start by distributing both th 5 and the negative 1 into their corresponding parentheses.
((5*2b)-(5*3)) > (10b - 15)
((-1*11b)+(-1*1)) > (-11b - 1)
so you have:
10b - 15 - 11b - 1 = 20
Next you would Combine like terms to get:
-b - 16 = 20
Add the 16 to both sides
-b = 36
and divide each side by -1
b = - 36
hope this helps
Answer:
12
Step-by-step explanation:
Given that
Current count of pushups = 8
Number of increase in pushups each day = 2
The desired pushup goal on daily basis = 30
Days require = x= ?
as we can conclude the number of pushups would increase by following sequence
8, 10, 12, 14, 16, ......30
Now as we can be the number of pushups by a constant number each day it means this sequence is arithmetic.
First term of our sequence is X1 and the final term is Xn, and the difference between two consecutive terms (Common Difference) is 2.
So
X1 = 8
Xn = 30
d = 2
Using the formula of nth term for arithmetic sequence
Xn = X1 + (n-1)d
Substituting the values
30 = 8 + (n-1)2
30-8 = (n-1)2
22 = 2n -2
22+2 = 2n
2n = 24
n = 24/2
n = 12
So, it means on the 12th day he will have to do 30 pushups if he starts from 8 and increase 2 pushups each day.
