Answer:
int main() {
int _2dArray[32][32];
for (int i = 0; i < 32; i++) {
for (int j = 0; j < 32; j++) {
_2dArray[i][j] = j + i * 32;
}
}
return 0;
}
Explanation:
Here is a generic C/C++ 2d array traversal and main function example. The rest you'll have to figure out based on what kind of app you're making.
Good luck!
Answer:
Following are the solution to this question:
Explanation:
This algorithm uses the divide and rule approach works, which splits the list into two sublists depending on if they are smaller or larger than the pivotal factor. It has O(n*log n) complexity.
It splits down the list in more than one version frequently till every sublist becomes based on a single element and fuses it to offer an ordered array. The merge type works according. It has O(n*log n) complexity.
Please find the attachment file of the sorting.
Answer:
3 amps
Explanation:
because as per ohm's law. "electric current is proportional to voltage and inversely proportional to resistance"
<span>make periodic adjustments on an as-needed basis. </span>
Answer: or element_id Specifies the relationship between the result of the calculation, and the elements used in the calculation
form form_id Specifies which form the output element belongs to
name name Specifies a name for the output element
Explanation: