Hi,
I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:
#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
short T;
cin >> T;
cin.ignore();
string str[100];
for(int i=0; i<T; i++)
{
getline(cin, str[i]);
}
for (int i = 0; i < T; i++)
{
stringstream ss(str[i]);
string tmp;
vector<string> v;
while (ss >> tmp)
{
// Let's capitalize it before storing in the vector
if (!tmp.empty())
{
transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
tmp[0] = toupper(tmp[0]);
}
v.push_back(tmp);
}
if (v.size() == 1)
{
cout << v[0] << endl;
}
else if (v.size() == 2)
{
cout << v[0][0] << ". " << v[1] << endl;
}
else
{
cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
}
}
return 0;
}
Answer:
Kindly check attached picture
Explanation:
Flowchart gives a graphical representation of a steps taken towers the execution of a program.
In the flowchart attached, A variable was initialized and set to 0 ; then a for loop was used to iterate integers 1 up to 10, for each number. It is added to the initialized variable sum until all the 10 integer numbers are added. The the average is obtained by dividing by 10.
Answer:
I don't understand the question
Answer:
#include<iostream>
using namespace std;
int main (){
int n1, n2;
cout<<"Enter 1st number";
cin>>n1;
cout<<"Enter 2nd number";
cin>>n2;
if(n1<n2){
cout<<"The 1st number is the smallest"<<endl<<" is= "<<n1;
}
else{
cout<<"The 2nd number is the smallest"<<endl<<" is= "<<n2;
}
}
return 0;
Answer:
input process and output hehe
