The function of exponential growth or decay is given as y= a(1 ± r)ˣ. y represents a function of exponential decay with 45%. The correct option is D.
<h3>What is exponential growth or decay function?</h3>
Consider the function:
y= a(1 ± r)ˣ
where m is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.
- If there is plus sign, then there is exponential growth happening by r fraction or 100r %.
- If there is negative sign, then there is exponential decay happening by r fraction or 100r %.
If we compare the given function with the exponential function, then it can be observed that the value of (1±r) is less than 1, therefore, the function will be of exponential decay.
Now, if the (1-r) is compared with 0.55 given in the function than the value of r will be,
1 - r = 0.55
-r = 0.55 - 1
-r = -0.45
r = 0.45
r = 45%
Hence, y represents a function of exponential decay with 45%.
Learn more about exponential growth and decay here:
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Answer:
x=(-1/10) is the answer of given algebra
length of big square
length of small square
difference between length of two square
=5.2-3.5
=1.7
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
2nd option
Step-by-step explanation:
Given
3x³ - 15x² - 4x + 20
step 1 ( group the first/second and third/fourth terms )
(3x³ - 15x² ) + (- 4x + 20)
step 2 ( factor each group )
3x² (x - 5) - 4(x - 5) ← note factor of - 4 ( not + 4 )
step 3 ( factor out (x - 5) from each term )
(x - 5)(3x² - 4)
