Answer:
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be .
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to .
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Answer:
Java solution (because only major programming language that has public static methods)
(import java.io.* before hand)
public static boolean s2f(String fileName, String text){
try{
PrintWriter out = new PrintWriter(new File(fileName));
out.println(text);
out.close();
return true;
}
catch(Exception e){
return false;
}
}