The square root of 26 is 5.0999... which rounds to 5.1
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By algebra properties we find the following relationships between each pair of algebraic expressions:
- First equation: Case 4
- Second equation: Case 1
- Third equation: Case 2
- Fourth equation: Case 5
- Fifth equation: Case 3
<h3>How to determine pairs of equivalent equations</h3>
In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:
First equation
(7 - 2 · x) + (3 · x - 11)
(7 - 11) + (- 2 · x + 3 · x)
- 4 + (- 2 + 3) · x
- 4 + (1) · x
- 4 + (5 - 4) · x
- 4 - 4 · x + 5 · x
- 4 · (x + 1) + 5 · x → Case 4
Second equation
- 7 + 6 · x - 4 · x + 3
(6 · x - 4 · x) + (- 7 + 3)
(6 - 4) · x - 4
2 · x - 4
2 · (x - 2) → Case 1
Third equation
9 · x - 2 · (3 · x - 3)
9 · x - 6 · x + 6
3 · x + 6
(2 + 1) · x + (14 - 8)
[1 - (- 2)] · x + (14 - 8)
(x + 14) - (8 - 2 · x) → Case 2
Fourth equation
- 3 · x + 6 + 4 · x
x + 6
(5 - 4) · x + (7 - 1)
(7 + 5 · x) + (- 4 · x - 1) → Case 5
Fifth equation
- 2 · x + 9 + 5 · x + 6
3 · x + 15
3 · (x + 5) → Case 3
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There is not enough info to answer this question.
Answer:
x = 10
Step-by-step explanation:
x = 4 + (4x-4) ^ (1/2)
First, we rewrite the expression:
x = 4 + (4x-4) ^ (1/2)
x = 2 (2+ (x-1) ^ (1/2))
x = 4 + 2 (x-1) ^ (1/2)
From here we get a solution for x = 10
To check it we substitute x = 10 in the expression:
10 = 4 + 2 (10-1) ^ (1/2)
10 = 4 + 2 (9) ^ (1/2)
10 = 4 + 2 (3)
10 = 4 + 6
10 = 10
Answer:
The solution is:
x = 10
