Answer:
x = 1, y = -1
Step-by-step explanation:
If we have the two equations:
and
, we can look at which variable will be easiest to eliminate.
looks like it might be easy to get rid of, we just have to multiply
by 2 and y is gone (as -6y + 6y = 0).
So let's multiply the equation
by 2.

Now we can add these equations

------------------------

Dividing both sides by 5, we get
.
Now we can substitute x into an equation to find y.

Hope this helped!
Step-by-step explanation:
The volume of a cube is

where a is the side length,
Note: If you want to remember this formula, know that a cube is basically a bunch of squares stacked on one another vertically and horizontally
The area of a square with side length a, is

If we multiply that by the height of the cube, which is a.

That is the easy way to derive the formula of the volume of a cube.
Back on track, we know the volume so we must solve for a.
1.

Assuming you took algebra, to isolate the variable a, we must undo it being raised to the third power.
To do this, we take the cube root of both sides
![\sqrt[3]{125} = \sqrt[3]{a {}^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B125%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7Ba%20%7B%7D%5E%7B3%7D%20%7D%20)
The cube root of 125 is 5 so

5 cm
2.

![\sqrt[3]{8} = \sqrt[3]{ {a}^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7Ba%7D%5E%7B3%7D%20%7D%20)

2 ft
3.


7 yd
4.


10 mm
5.


12 in. or 1 ft
6.


1 m
4.1 rounded to the nearest ones is 4
Answer: the function as they change value from one interval to the next
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x