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3 years ago

What are the answers

Mathematics

2 answers:

ale4655 [162]3 years ago

8 0

The solution to the system of equations, though we can solve using substitution, can also be found by graphing these equations. If you graph these equations, look for where they intersect (it should be one point!).

-5x + 6 = 3x - 2

6 = 8x - 2

8x = 8

x = 1

y = 3(1) - 2

y = 3 - 2

y = 1

Hope this helps!! :)

tekilochka [14]3 years ago

7 0

Answer:

x = 1, y = 1

Step-by-step explanation:

Use system of equations to solve for x and y by using substitution

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3 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

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This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

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kenny6666 [7]

Answer:

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Step-by-step explanation:

since it is said it is a parallelogram so opposite sides are equal

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