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Cloud [144]
3 years ago
7

What is 19/25 as decimal

Mathematics
2 answers:
horsena [70]3 years ago
4 0
The decimal for 19/25 is <span>0.76</span>
Radda [10]3 years ago
3 0
Well first we need to find how we can turn 25 into 100 
Well one way would be to multiply by 4 
25 x 4 = 100 

Since we multiplied the bottom number by 4 we should multiply the top number by 4. 

So..
19 x 4 = 76

So our new fraction is..
 76 
-----
100

Now we can easily turn this into a decimal. 
76/100 = 0.76 

Answer = 0.76 

Good Luck! :)
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Please help me with this question I’m so confused
zavuch27 [327]

s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 10( \frac{1}{2} ) +  \frac{1}{2} ( - 2) {( \frac{1}{2}) }^{2}  \\ s = 10( \frac{1}{2} ) +  \frac{1}{2} ( - 2)(  \frac{1}{4} ) \\ s = 5 + ( - 1)( \frac{1}{4} ) \\ s = 5 + ( -  \frac{1}{4} ) \\ s = 5 -  \frac{1}{4}  \\ s =  \frac{20}{4}  -  \frac{1}{4}  \\ s =  \frac{19}{4}

Hope it helps

Please give brainliest

4 0
2 years ago
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Help!! Math question
aksik [14]
18 - 7x = -20.52.5 = 7xx = 5/14 (c)


5 0
3 years ago
Read 2 more answers
Lim as x-&gt;ln2 of ((e^3x)-8)/((e^2x)-4)
andriy [413]
X ⇒ ln (2) 

e^3 x - 8/e^2 x - 4

7 0
3 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
If you are dealt 5 cards at random from a standard deck of playing cards, what is the probability that at most 4 of them are spa
alexira [117]

Answer:

Step-by-step explanation:

No of ways in which 5 cards are chosen is N=^{52}C_5

No of ways in which at most  4 cards are spades N_0=Total ways-5 spades

=^{52}C_5-^{13}C_5

Probability that at most 4 cards are spade P=\frac{N_0}{N}

P=\frac{^{52}C_5-^{13}C_5}{^{52}C_5}

P=\frac{2598960-1287}{2598960}

P=\frac{2597673}{2598960}=0.9995

3 0
3 years ago
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