Together, the area of the two bases is
(6 in)×(8 in) = 48 in²
The lateral area is the product of the height of the prism (2 in) and the perimeter of the base (6 in +8 in +10 in), so is
(2 in)×(24 in) = 48 in²
The total area is the sum of these
area = 48 in² +48 in² = 96 in² . . . . . . . . . matches the 3rd selection
Answer:
Boat traveled 553.24 feet towards the lighthouse.
Step-by-step explanation:
In the figure attached AB is the light house of height 200 feet.
Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'
so 1' =
degree
so angle of elevation at point C = 14 + 
So angle of elevation from C = (14 + 0.87) = 14.87°
Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 +
= 45.17°
Now we have to calculate the distance CD, traveled by the boat.
In ΔABC
tan14.87 = 
0.2655 = 
BC = 
BC = 753.239 feet
Similarly in ΔABD
tan45.17 = 
1 = 
BD = 200 feet
So distance CD = BC - BD
CD = 753.239 - 200
= 553.24 feet
Therefore, Boat traveled 553.24 feet towards the lighthouse.