Answer:
it would be a triangle
Step-by-step explanation:
Do good!
The area of the sector is
.. Asector = (1/2)r^2*θ = (1/2)*(8.35 ft)^2*(π*260°/180°) ≈ 158.195 ft^2
The area of the triangle is
.. Atriangle = (1/2)r^2*sin(θ) = (1/2)*(8.35 ft)^2*sin(100°) ≈ 34.332 ft^2
The shaded area is
.. A = Asector +Atriangle
.. = 158.195 ft^2 +34.332 ft^2
.. ≈ 192.5 ft^2
Answer:
The point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.
Step-by-step explanation:
The distance between two points (x₁, y₁) and (x₂, y₂) on the x-y plane can be calculated with:
√((x₁ - x₂)² + (y₁ - y₂)²)
So in this case, with the points (-3, 2) and (4, 0), the distance is:
√((-3 - 4)² + (2 - 0)²)
√(49 + 4)
√(53) ≈ 7.28
Since 7.28 > 5, the point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.
Hello :
<span>D= 3sin(8 pi t) - 2
t=0 : D =3sin(0) - 2 = 0-2 = - 2
</span><span>objects position at t= 0 is : (0 , -2)</span>
You didn't clarify what the angle is needed for, but still, I'd say never.
If you know two sides of a right triangle you can always find the third using the pythagorean theorem.
Once all sides are known, you can find the three angles: one is surely right, since you have a right triangle. The other two can be found using the sine law.
