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Julli [10]
3 years ago
10

What is the value of x in the equation , when y = 3?

Mathematics
2 answers:
sashaice [31]3 years ago
4 0

Answer:

9

Step-by-step explanation:

I think the answer would be 9 but I'm not for sure

sergij07 [2.7K]3 years ago
4 0

Answer:

the answer is x=6

Step-by-step explanation:

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Write a for loop that computes the following sum: 5 10 15 20 ... 485 490 495 500. The sum should be placed in a variable sum tha
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The solution is in the attachment

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3 years ago
A right circular cylinder is changing shape. The radius is decreasing at the rate of 2 inches/sec while it's height is increasin
Savatey [412]

Answer:

<h3> 552.640in³/s</h3>

Step-by-step explanation:

Volume of a cylinder is expressed as;

V = \pi r^2 h

\frac{dV}{dt} = \frac{dV}{dr} \frac{dr}{dt} +\frac{dV}{dh} \frac{dh}{dt}

dV/dr = 2πrh

dV/dr = 2π(4)(6)

dV/dr = 48(3.14)

dV/dr = 150.72in³/m

dV/dh = πr²

dV/dh = 3.14(4)²

dV/dh = 50.24

Given

dh/dt = 5in/s

dr/dt = 2in/s

Substitute into the dV/dt

dV/dt = 150.72(2)+50.24(5)

dV/dt = 301.44 + 251.2

dV/dt= 552.640in³/s

The volume is changing at the rate of  552.640in³/s

7 0
3 years ago
In Lila's classroom there are red chairs, yellow chairs, and blue chairs. There are 5 red chairs.
Alex777 [14]

Answer:

Seven

Step-by-step explanation:

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8 0
3 years ago
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Answer:

45

Step-by-step explanation:

3 0
3 years ago
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Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
4 years ago
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