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castortr0y [4]
3 years ago
15

Find the smallest zero for the function h(x)=4x^2-8x-60.

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
H(x) = 4x² - 8x - 60
    0 = 4x² - 8x - 60
    0 = 4(x²) - 4(2x) - 4(15)
    0 = 4(x² - 2x - 15)
    4               4
    0 = x² - 2x - 15
    0 = x² - 5x + 3x - 15
    0 = x(x) - x(5) + 3(x) - 3(5)
    0 = x(x - 5) + 3(x - 5)
    0 = (x + 3)(x - 5)
    0 = x + 3    or    0 = x - 5
  - 3        - 3        + 5      + 5
    3 = x       or       5 = x
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