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3 years ago

15

Find the smallest zero for the function h(x)=4x^2-8x-60.

1 answer:

ankoles [38]3 years ago

8 0

H(x) = 4x² - 8x - 60
0 = 4x² - 8x - 60
  0 = 4(x²) - 4(2x) - 4(15)
  0 = 4(x² - 2x - 15)
4 4
0 = x² - 2x - 15
0 = x² - 5x + 3x - 15
0 = x(x) - x(5) + 3(x) - 3(5)
0 = x(x - 5) + 3(x - 5)
0 = (x + 3)(x - 5)
0 = x + 3 or 0 = x - 5
- 3 - 3 + 5 + 5
3 = x    or    5 = x

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