Answer:
Option C, F(x) = (x+2)/(x+1)
Answered by GAUTHMATH
Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
<u>Answer:</u>
The number of tickets bought is 1000 adults tickets and 700 children were present
<u>Explanation:</u>
Let the number of children and adults present in the circus be x and y respectively
According to question,
Then, x + y = 1700 ……………..equation (1)
And, cost of ticket to circus for children and adult be 19, 42 respectively
Total cost of ticket;
for adults = 42y; for children = 19x
19x + 42y = 55300 …………………equation (2)
Multiplying equation (1) by 19
19x + 19y = 32300 ……………… eqn (3)
Subtracting equation 1 and 3, we get
23y = 23000
y = 1000
putting this value in eq (1), we get x = 700
Therefore, 1000 adults and 700 children were present
.
72 is the length d of how deep end in feet}
(7 + 5i) - ( -9 + i)
= 7 + 5i - (-9) - (i)
= 7 + 5i + 9 - i
= 16 + 4i
= 4i + 16
