Answer:
d= -3567
Step-by-step explanation:
d+3567=0
subtract 3567 from both sides
d= -3567
Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
Kevin will water both of his plants on the 15th.
The lowest common multiple of 3 and 5 is 15. Therefore, he will water both then.
For the points you've given, the correct answer is not listed! One way to solve the problem is just to use a graph -- the points are not far away from the origin, and they have whole number coordinates. (See graph.)
Slopt = "rise" / "run" so to get from (2, 2) to (4, 3), you "rise" +1 and "run" +2. The slope is 1/2.
If the points are (2, 2) and (4, 3), then the slope would be 2.
You can always use a formula to find the slope:
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
which tells the slope of a line joining points
![(x_1,y_1)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29)
and
![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
.
The formula says
Slope = (second y minus first y) / (second x minus first x)
It always works unless
![x_1=x_2](https://tex.z-dn.net/?f=x_1%3Dx_2)
, in which case the line is vertical and has NO defined slope.
This is correct, but in what sense are you needing an answer ?