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Elan Coil [88]
3 years ago
12

2) Solve the System of Equations using Substitution. -3x+2y=12 x=2y-8

Mathematics
2 answers:
Nady [450]3 years ago
6 0

Answer:

x=-2. y=3

Step-by-step explanation:

So, it tells us that x=2y-8.

Now substitute x into the equation.

-3(2y-8)+2y=12

- 6y+24+2y=12

-4y+24=12

-4y=-12

y=-12/-4

y=3

Now that we know that y=3 substitute y into the second equation equation.

x=2(3)-8

x=6-8

x=-2

So in the end x=-2 and y=3

Hope this helps

Ne4ueva [31]3 years ago
5 0

Answer:

y=3, and x= -2

Step-by-step explanation:

-3x= -2y+12

x=2y-8

3x=2y-12

3x=6y-24

2y-12=6y-24

-4y=-12

y=3

x= -2

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. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the
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3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
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Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

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             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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