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iVinArrow [24]
4 years ago
10

How to do the circumference of a circle

Mathematics
2 answers:
Vlad [161]4 years ago
8 0

The formula is C=\pid.
SIZIF [17.4K]4 years ago
7 0
C=3.14•diameter
C is circumfrence
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The sum of nine consecutive positive integers is 99. what is the largest of these integers
Oksana_A [137]

Answer:

I believe it is 200. Forgive me if its wrong-

6 0
3 years ago
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Really easy points!!!!!! Please solve for all three answers.
katen-ka-za [31]

Answer:

1/64, 1/256, 1/1024

Step-by-step explanation:

To get from 16 to 4 we multiply by 1/4

To get from 4 to 1 we multiply by 1/4

Each time we multiply by 1/4

The next term would be 1/16 * 1/4

1/16 * 1/4 = 1/64

The take that term 1/64 and multiply by 1/4

1/64*1/4 = 1/256

Finally take 1/256 and multiply by 1/4

1/256*1/4 =1/1024

8 0
4 years ago
Simplify the radical expression.
GREYUIT [131]

Answer:

c

Step-by-step explanation:

160 = 16 * 10 =  4 * 4 * 2 * 5 = 2 * 2 * 2 * 2 * 2 *5

-4\sqrt{160} = -4\sqrt{2*2*2*2*2*5}\\\\= -4*2*2\sqrt{2*5}\\\\= -16\sqrt{10}

5 0
3 years ago
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In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website
expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is n = 10

The significance level is \alpha = 1 - 0.05 = 0.95

The estimate, which is the sample standard deviation, is of s = 0.8772.

Now, we have to find the critical values for the Pearson distribution. They are:

\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228

\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004

The confidence interval for the population variance is:

\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}

\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}

0.3641 < \sigma^2 < 2.5646

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

\sqrt{0.3641} = 0.6034

\sqrt{2.5646} = 1.6014

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0
3 years ago
Substitute method 9x -2y =3 3x -6 = y
Verizon [17]
Answer:(-3 , -15)
X= -3 and Y= -15
6 0
4 years ago
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