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weeeeeb [17]
3 years ago
13

2}{6} - \frac{1}{6} " alt=" \frac{2}{6} - \frac{1}{6} " align="absmiddle" class="latex-formula">
please help
Mathematics
1 answer:
notka56 [123]3 years ago
4 0
The answer is 1 over 6, 1/6.
Since the denominators (bottom numbers) are the same then they don't need to be changed and can therefore be simplified by subtraction.
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Help please math problem
r-ruslan [8.4K]

Answer:

Hope this will help you and hope you understand my handwriting

7 0
3 years ago
What is 5x < 15 can someone sollve it plz
Dmitry [639]

Answer:

x <  3

Step-by-step explanation:

5 0
2 years ago
PLEASE HELP ME!!!!! I HAVE TRIED THIS QUESTION 5X ALREADY AND I STILL CANNOT GET THE RIGHT ANSWER!!! I KNOW THE ANSWER BUT I HAV
kirill [66]

Answer:

x = 3 and y = 2

or

(3,2)

Step-by-step explanation:

first equation (LCM = 3 x 4 x 5 = 60)

(x+2)/5 - (9-x)/3 = (y - 6)/4

12(x+2) - 20(9-x) = 15(y - 6)

12x + 24 - 180 + 20x = 15y - 90

32x - 15y = -90 - 24 + 180

32x - 15y = 66

second equation:

8(x + 2) - (2x + y) = 2(x + 13)

8x + 16 - 2x - y = 2x + 26

6x - y + 16 = 2x + 26

4x - y = 10

Now you have 2 equations:

4x - y = 10  ---> y = 4x - 10

32x - 15y = 66

Substitute   y = 4x - 10 into 32x - 15y = 66

32x - 15(4x - 10) = 66

32x - 60x + 150 = 66

-28x = -84

    x = 3

    y = 4(3) - 10

    y = 12 - 10

    y = 2

Solutions: x = 3 and y = 2

6 0
3 years ago
I need help with 25.
noname [10]

Sum of linear pair of angles = 180°

so

<EFG + <GFH = 180°

2n + 21 + 4n + 15 = 180°

6n + 36 = 180°

6n = 144

n = 24

<EFG = 2(24) + 21 = 69°

<GFH = 4n + 15 = 4(24) + 15 = 111°

6 0
3 years ago
If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
ivolga24 [154]

Answer:

-\sqrt{5}

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

  • One answer with positive square root
  • One answer with negative square root

For example, for the equation:

x^{2}=3

If we take the square root of both sides, the answers will be:

x=\sqrt{3} \text{ or } x= -\sqrt{3}

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and \sqrt{5}. Therefore, the 3rd root of the polynomial function f(x) had to be -\sqrt{5}

It seems you made error while writing option B, it should be - square root of 5.

4 0
3 years ago
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