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Marina CMI [18]
3 years ago
5

Yosef purchased a new sweater. The total price of the sweater, including the 8% sales tax, was $16.74. What was the retail cost

of the sweater (before tax). $18.08 $16.66 $15.40 $15.50
Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

15.40, lol yeet, this one's EZ

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Instructions: Find the common difference of the arithmetic sequence.<br> 7.05, 7.15, 7.25,7.35, 7.45
zzz [600]
I believe that the common difference would be.10
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What does 48% equal as a number
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to convert a percent to a whole number just divide by 100

Step-by-step explanation:

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6 0
3 years ago
Please help and explain with these 2 math questions!!!!!!
Volgvan

1)  -10x+y=4

Now, you should substitute x in every situation.

* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>

<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>

<u />*x=0 => -10*0+y=4... <u>y=4</u>

<u />* x=1 =>  -10*1+y=4... -10+y=4... <u>y=14</u>

<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>

<u>2)</u> -5x-1=y

For example: x=0

-5*0-1=-1

<u>
</u>



6 0
3 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
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