781÷26<br>26×3=78<br>is answer 3 remainder 1 or 30 remainder 1

In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

$n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )$

where $n\left ( N\cup E\right )=$ Students either nose or ear Pierced

$n\left ( N\cap E\right )=$ no of students having both nose and ear pierced

$40=7+36-n\left ( N\cap E\right )$

$n\left ( N\cap E\right )=43-40=3$

3 0

3 years ago

Consider the parent function f(x)=e^x and transformed function g(x)=-f(x)-4. Which features of function F function G are differe

eduard

There are no results for Consider the parent function f(x)=e^x and transformed function g(x)=-f(x)-4. Which features of function F function G are different

3 0

3 years ago

What is 1/4 (5y-3)+1/16 (12y+17

netineya [11]

What is the question? If you are only trying to expand the expression then the answer would be:

1/4 (5y-3)+ 1/16 (12y+17)

(5y/4) – (3/4) + (12y/16) + (17/16)

1.25y – 0.75 + 0.75y + 1.0625

2y + 0.3125

If you are trying to find for y, then you forgot to equate it to 0, that is:

2y + 0.3125 = 0

2y = -0.3125

6 0

3 years ago

You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo

stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean $(\mu) = 5.75913$