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Rainbow [258]
3 years ago
8

7 big ones cost 280,000 how many could u buy with 120,000

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer:

You can buy 2 because 120,000 times 2 = 240,000

Step-by-step explanation:


Bond [772]3 years ago
7 0

Answer:

you can buy three

Step-by-step explanation:

first, divide 280,000 by 7

then, 120,000 by 40,000 to get 3.

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0.5x-7= 0.3 solve the equation<br><br><br><br><br>​
Lena [83]

Answer:

<h3>\boxed{ \bold{ \boxed{ \sf{x = 14.6}}}}</h3>

Step-by-step explanation:

\sf{0.5x - 7 = 0.3}

Move 7 to right hand side and change it's sign

⇒\sf{0.5x = 0.3 + 7}

Add the numbers

⇒\sf{0.5x = 7.3}

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⇒\sf{ \frac{0.5x}{0.5}  =  \frac{7.3}{0.5} }

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Hope I helped!

Best regards!!

3 0
4 years ago
If h=11 units and r =2 units then what is the approximate volume of the cone
melisa1 [442]

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8 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

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3 0
3 years ago
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