Answer:
Filterable blood components include water, nitrogenous waste, and nutrients that will be transferred into the glomerulus to form the glomerular filtrate. Non-filterable blood components include blood cells, albumins, and platelets, that will leave the glomerulus through the efferent arteriole.
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Answer:
a. they are central to the re-synthesis of nucleotides from bases in salvage reactions.
Explanation:
Phosphoribosyltransferases are the enzymes that are involved in salvage pathways to reuse the free purines and pyrimidines to make nucleotides. Metabolic degradation of nucleotides releases purines and pyrimidines which in turn enter the salvage pathway to be reused in the formation of new nucleotides. These metabolic pathways that make new nucleotides by reusing the free purines and pyrimidines are called salvage pathways.
Example: Adenosine phosphoribosyltransferase is the enzyme that catalyzes the formation of adenine nucleotide from free adenine and PRPP (5-phosphoribosyl-1-pyrophosphate).
Answer: The answer is C, the individual alleles that make up the gene must SEGREGATE (which means separate) during gamete formation, hence the name “law of segregation”
Explanation: Hope this helps
Answer:
D. Genes A and B are likely to stay together, but they are more likely to become separated from gene C since a crossover is more likely to occur in the longer space between them.
Explanation:
Cross over between homologous chromosomes occurs during meiosis I. A synapsis is formed and non sister chromatids exchange genetic material between each other. If gene A and gene B are close to each other on a chromosome, they most likely will show linkage. During cross over these genes will have more probability to get inherited together from the parent and hence offspring with parental combination will be more in number. Since gene C is farther away from the two genes, it will show normal cross over and recombination. Offspring produced will have almost equal parental and new combination.