Answer:
-5-1/4
Step-by-step explanation:
Subtract 3/5b from both sides
8/5b+2=10
subtract 2 from both sides
8/5b=8
Divide both sides by 8/5
b=5
To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
Answer:
6, if i did it right in my head...
Step-by-step explanation:
Let x = first number, and y = second number.
x + y = 40 (1)
x - y = 6.5 (2)
Rearrange (2)
y = x - 6.5 (3)
Sub (3) in (1)
x + (x - 6.5) = 40
2x - 6.5 = 40
2x = 33.5
x = 16.75 (4)
Sub (4) in (1)
16.75 + y =40
y = 23.25
x * y = 16.75 * 13.25 = 221.9375
The product is 221.9375