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1 answer:
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Answer:
0 ; 2/9 ; 1
Step-by-step explanation:
In a roll of two dice ;
The sample space = (Number of faces on die)^number of dice rolled = 6^2 = 36
The total possible outcome = sample space = 36
The probability of an event (A) :
P(A) = number of required outcome / number of total possible outcomes
find the probability for total: a) 1,
P(total of 1)
Number of 1 total = 0
Hence, P(total of 1) = 0
b) 4 or 6;
Number of 4 total = 3
Number of 6 total = 5
3 /36 + 5 / 36 = 8/36 = 2/9
c) <13
P(total < 13)
Number of total < 13 = 36
36 / 36 = 1
We want the integral of the standard normal from -z to z to be 0.85. Let's look at some standard normal tables and pick the right one.
It's easy to find the Erf one, which is the integral of the unit normal from 0 to z. That will be exactly half of the integral from -z to z. So we look for the z value corresponding to a probability of 0.425 in that table and find
z = 1.44
Answer: 1.44
[figure from Wikipedia]
