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e-lub [12.9K]
2 years ago
9

Oi anybody who solves this quick get 50 pts​

Mathematics
2 answers:
liraira [26]2 years ago
6 0
I believe the answer is B.
Aloiza [94]2 years ago
5 0

Answer:

l like ya g

Step-by-step explanation:

I forgot mostly uHm

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Based on what you know what is the measure of m
Bond [772]

Answer:

59 degrees, 44 plus 77 is 121, subtract from 180

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3 years ago
What is the answer to this math problem??
lakkis [162]

Answer:

A

Step-by-step explanation:

given \frac{1}{49^2}

note that 49² = 2401, hence

\frac{1}{49^2} = \frac{1}{2401} → A


4 0
2 years ago
Without graphing, classify the following system as independent, dependent, or inconsistent.
Galina-37 [17]

Answer:

Step-by-step explanation:

There is a missing operator in the second equation.

If the equation is 4x - 8y = 4, then the system is dependent. The second equation is a non-zero multiple of the first.

3 0
2 years ago
The sum of two numbers is 54. The smaller number is 18 less than the larger number. What are the numbers?
igomit [66]

Answer:

The larger number is 37.  This makes the smaller number 56 - 37, which is 19.

Step-by-step explanation:

 

The first step is to pick variables for the two numbers.  Lets call the smaller number x and the larger number y.

Since the sum of the two numbers is 56, this means that x + y = 56.  Let's call this equation 1 and save it for later.

 

The next sentence says:

The smaller number is 18 less than the larger number.  So, 18 less than the larger number would be y - 18.  So, the smaller number must be equal to this, so

 

x = y - 18

 

Replace the x in equation 1 with y - 18

 

x + y = 56

(y-18) + y = 56   (replace x with y-18)

2y - 18 = 56        (add the y's)

2y = 74               (add 18 to both sides)

y = 37                 (divide both sides by 2)

 

So, the larger number is 37.  This makes the smaller number 56 - 37, which is 19.

 

Hope this helps!!  :)

8 0
2 years ago
Somebody give me the answer to this
jeka57 [31]

Answer:

-2v = (-2x3, -2x4) = (-6,-8)

4 0
3 years ago
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