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2 years ago

Oi anybody who solves this quick get 50 pts

Mathematics

2 answers:

liraira [26]2 years ago

6 0

I believe the answer is B.

Aloiza [94]2 years ago

5 0

Answer:

l like ya g

Step-by-step explanation:

I forgot mostly uHm

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Find the radius of a circle using the Pythagorean theorem, given that the center is at (1, 5) and the point (5, 1) lies on the c

Assoli18 [71]

Given :

Center of circle, C = ( 1 , 5 )

Point on circle, P = ( 5 , 1 )

To Find :

The radius of a circle.

Solution :

We know, radius of circle is the distance between center and point of circle.

Distance between two points A(p,q) and B(r,s) is given by :

$D = \sqrt{(p-r)^2+(q-s)^2}$

So, distance between the points (1, 5) and (5, 1) is :

$D = \sqrt{(1-5)^2+(5-1)^2}\\\\D = 5.66 \ units$

Therefore, radius of circle is 5.66 units.

Hence, this is the required solution.

4 0

3 years ago

If r + t = 10 and -r + t = 4, What is the value of 5r + 8t?

ikadub [295]

Answer:

Step-by-step explanation:

Start solving using simultaneous equation,From there, we have r to be 3 and t to be 7

7 0

3 years ago

Find the sum or difference (5b-9)-3(8-2b)

True [87]

<span>Simplifying (5b + -9) + -3(8 + -2b) = 0 Reorder the terms: (-9 + 5b) + -3(8 + -2b) = 0 Remove parenthesis around (-9 + 5b) -9 + 5b + -3(8 + -2b) = 0 -9 + 5b + (8 * -3 + -2b * -3) = 0 -9 + 5b + (-24 + 6b) = 0 Reorder the terms: -9 + -24 + 5b + 6b = 0 Combine like terms: -9 + -24 = -33 -33 + 5b + 6b = 0 Combine like terms: 5b + 6b = 11b -33 + 11b = 0 Solving -33 + 11b = 0 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '33' to each side of the equation. -33 + 33 + 11b = 0 + 33 Combine like terms: -33 + 33 = 0 0 + 11b = 0 + 33 11b = 0 + 33 Combine like terms: 0 + 33 = 33 11b = 33</span>

5 0

3 years ago

Read 2 more answers

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

6 0

3 years ago

Need help on this question

AnnZ [28]

Answer:

Step-by-step explanation:

arc between cars = 360°/25 = 14.4°

θ = 14.4° × π/180 ≅ 0.2512 radian

r = 150/2 = 75 ft

s = rθ = 75×0.2512 = 18.84 ft

area of circle = πr² = 75²π ≅ 17,662.5 ft²

area of sector = 17,662.5/25 = 706.5 ft²

6 0

2 years ago

Oi anybody who solves this quick get 50 pts​

Oi anybody who solves this quick get 50 pts