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vitfil [10]
3 years ago
5

What is 5x^2 -17x-12=0

Mathematics
1 answer:
nadezda [96]3 years ago
6 0

Move all terms to the left side and set equal to 0. Then set each factor equal to 0.

The answer:

x = 4, -3/5

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Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
Determine the intercepts of the line.
Alina [70]

Answer:

x-intercept: (-250, 0)

y-intercept: (0, 100)

Step-by-step explanation:

Look for you the line intercepts the x-axis and y-axis. That's where the intercepts are located.

8 0
3 years ago
Read 2 more answers
Work out the size of angle x forty two degrees and one hundred and one hundred and twenty three degrees
Snezhnost [94]

Answer:

x = 28

Step-by-step explanation:

With 3 angles I'm guessing its a triangle so all triangles equal 180 degrees

42 + 110 = 152

180 - 152 = 28

3 0
3 years ago
Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
OlgaM077 [116]

Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

3 0
3 years ago
The triangles are similar. what is the value of x ?
jonny [76]

\dfrac{32}{4x+12}=\dfrac{8}{15}\\\\ \dfrac{8}{x+3}=\dfrac{8}{15}\\\\ x+3=15\\\\ x=12

6 0
3 years ago
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