Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Solution:
<u>We know that:</u>



<u>Simplify the equation to find the percent off:</u>

![84\% + \bold{16\%} = 100\% \space\ \space\ \space\ \ \ \ \ [Rounded]](https://tex.z-dn.net/?f=84%5C%25%20%2B%20%5Cbold%7B16%5C%25%7D%20%3D%20100%5C%25%20%5Cspace%5C%20%5Cspace%5C%20%5Cspace%5C%20%5C%20%5C%20%5C%20%5C%20%5BRounded%5D)
This means that the <u>original price</u> has decreased about 16%.
If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².
We have the ratio:

Area of the smaler triangle = x
Area of the larger triangle = 567 cm²
Therefore we have the equation:

<h3>Answer: C. 63 cm²</h3>