4. Two straight wires are parallel and carry currents of 1.2 A in opposite directions, as shown. Find the direction of the magne
tic field produced by the current in Wire 1 at the location of Wire 2 and mark the direction directly on your printed diagram using the direction symbols indicated. Label the symbol for the field direction B. Then find the direction of the magnetic force on Wire 2, mark it with the appropriate one of the direction symbols and label the force direction F. Finally, explain how your answer for the magnetic field and magnetic force would have changed if the current in Wire 1 had been reversed, but the current in Wire 2 remained the same, so that both currents were in the same direction.
1 answer:
The directions of magnetic force and magnetic field lines are shown in the figure.
The direction to find out the magnetic field lines is given by right hand curl rule. If the thumb shows the direction of current, then the curling fingers show the direction of magnetic field lines.
The direction of force can be given by right hand thumb rule, where
Thumb - Direction of magnetic field lines
Forefinger - Magnetic force
Centre finger - Current
Such that forefinger, centre finger and thumb must be at 90 degrees to each other.
The direction to find out the magnetic field lines is given by right hand curl rule. If the thumb shows the direction of current, then the curling fingers show the direction of magnetic field lines.
The direction of force can be given by right hand thumb rule, where
Thumb - Direction of magnetic field lines
Forefinger - Magnetic force
Centre finger - Current
Such that forefinger, centre finger and thumb must be at 90 degrees to each other.
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Answer:
Velocity of electron along x direction is 57.9 m/s
Explanation:
The uncertainty in x coordinate of electron, Δx = 0.200 mm = 0.2 x 10⁻³ m
Let vₓ be the x component of electrons velocity.
The uncertainty in x component of electrons momentum is:
Δpₓ = mΔvₓ
Here m is mass of the electron.
The uncertainty in velocity x component is 1% i.e. 0.01.
So, the above equation can be written as :
Δpₓ = 0.01mvₓ ....(1)
The minimum uncertainty principle is:
....(2)
Here h is Planck's constant.
From equation (1) and (2),
Substitute 0.2 x 10⁻³ m for Δx, 9.1 x 10⁻³¹ kg for m and 6.626 x 10⁻³⁴ m²kg/s in the above equation.
vₓ = 57.9 m/s