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skelet666 [1.2K]
3 years ago
12

PLEASE HELP! Explain how energy travels outward from the core and is emitted from the Sun. Include what happens in each layer of

the Sun.
Physics
2 answers:
xxMikexx [17]3 years ago
8 0
Fusion occurs in the Sun's core, releasing energy that is transferred outward. Once in the radiative zone, gamma rays are transferred by radiation. They are converted to other types of photons, which move into the convective zone, where they are transferred by convection. Finally, energy is emitted from the photosphere.
cricket20 [7]3 years ago
5 0

Answer:

fusion occurs in the core. it releases energy and its transferred outward. Gamma rays are transferred by radiation when in the radiative zone. then they are converted to other photons that move into the convective zone. there they are transferred by convection. lastly energy is emitted from the photosphere.

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a block of wood of density 0.8 gram per centimetre cube has a volume of 60 cm3 the mass of block will be...?​
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Density =mass/Volume

0.8=mass/60
Mass=0.8*60
Mass=48g
4 0
2 years ago
PLEASE HELP ME WILL GIVE BRAINLIEST
weqwewe [10]

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A.always changing

Explanation:

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Two piles of heavy boxes must be lifted onto a shelf. Each pile has 20 boxes and each box is the same size and weight. Tom and c
Murrr4er [49]
Tom used more Force but over a shorter distance. Tom and Claudia both did the same amount of work.
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Determine the minimum work per unit of heat transfer from the source reservoir that is required to drive a heat pump with therma
Sloan [31]

Answer:

The minimum work per unit heat transfer will be 0.15.

Explanation:

We know the for a heat pump the coefficient of performance (C_{HP}) is given by

C_{HP} = \dfrac{Q_{H}}{W_{in}}

where, Q_{H} is the magnitude of heat transfer between cyclic device and    high-temperature medium at temperature T_{H} and W_{in} is the required input and is given by W_{in} = Q_{H} - Q_{L}, Q_{L} being magnitude of heat transfer between cyclic device and low-temperature T_{L}. Therefore, from above equation we can write,

&& \dfrac{Q_{H}}{W_{in}} = \dfrac{Q_{H}}{Q_{H} - Q_{L}} = \dfrac{1}{1 - \dfrac{Q_{L}}{Q_{H}}} = \dfrac{1}{1 - \dfrac{T_{L}}{T_{H}}}

Given, T_{L} = 460 K and T_{H} = 540 K. So,  the minimum work per unit heat transfer is given by

\dfrac{W_{in}}{Q_{H}} = \dfrac{T_{H} - T_{L}}{T_{H}} = \dfrac{540 - 460}{540} = 0.15

8 0
3 years ago
A light, flexible cable is wrapped around a solid cylinder with mass 3.3 kg and a radius of 0.8 meters. The cylinder rotates on
kari74 [83]

Answer:

9.16rad/s^2

Explanation:

We are given that

Mass,m_1=3.3 kg

Radius,r=0.8 m

m_2=4.9 kg

Height,h=2.9 m

We have to find the angular acceleration of the cylinder.

According to question

4.9g-T=4.9a

Tr=I\alpha

Where

\alpha=\frac{a}{r}

Tr=\frac{1}{2}m_1ra

T=\frac{1}{2}m_1a=\frac{1}{2}(3.3)a

Substitute the value

4.9g-\frac{1}{2}(3.3a)=4.9a

4.9\times 9.8=4.9a+\frac{3.3a}{2}

Where g=9.8 m/s^2

48.02=a(4.9+1.65)=6.55a

a=\frac{48.02}{6.55}=7.33m/s^2

Angular acceleration,\alpha=\frac{a}{r}=\frac{7.33}{0.8}=9.16rad/s^2

7 0
3 years ago
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