Answer:
B:31.5
Step-by-step explanation:
Find areas of both rectangles by multiplying the 2 given values (12 & 15)
Take the sides parallel to the triangles non-hypotenuse sides (3 & 3)
Take both values and add them over 2
Receive the answer 4.5
Add that to the rectangle values for an answer of 31.5
Hope this helps
Have a good day
Answer:
80
Step-by-step explanation:
mean = 140+20=160
160/2
= 80
Parallel lines, slope is the same so
1) 3x+8y = 12
8y = -3x + 12
y = -3/8(x) + 3/2, slope = -3/8
slope of a line that is parallel = -3/8
2)5x+4y = 5
4y = -5x + 5
y = -5/4(x) + 5/4; slope is -5/4
slope of a line that is parallel = -5/4
--------------------
perpendicular, slope is opposite and reciprocal
3)
3x+8y = 11
8y = -3x + 11
y = -3/8(x) + 11/8. slope = -3/8
slope of perpendicular line = 8/3
4)
x = -7, slope is undefined
so slope of perpendicular line is 0
5)
3x+2y = 12
2y = -3x + 12
y = -3/2(x) + 6 ; slope = -3/2
5x - 6y = 8
6y = 4x - 8
y = 2/3(x) - 4/3; slope is 2/3
slope is opposite and reciprocal, so the equals are perpendicular
6)
3x + y = 5
y = -3x + 5; slope = -3
6x + 2y = -15
2y = -6x - 15
y = -3x - 7.5; slope = -3
both have slope = -3 so equations are parallel
B. Between 20 and 25 minuets
Brooke's speed is decreasing between 20 and 25 minutes. According to the graph Brooke's speed is decreasing during that time period.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
