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tresset_1 [31]
3 years ago
6

For a treasure hunt game, 300 balls are hidden. Of the balls that are hidden, 40% of them are yellow and the rest are white. Sal

ly’s team finds 20% of the yellow balls and 80% of the white balls. How many balls did Sally’s team find?
Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

poopo

Step-by-step explanation:

UNO [17]3 years ago
3 0

Answer: sorry im useless here

Step-by-step explanation:

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(cube√7x)^2

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How do you write 1/2 as a decimal
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How do I write an equation for each parabolas?
fredd [130]

Step-by-step explanation:

  1. In the first parabola it opens on the left and the equation of parabola can be expressed as,

              in vertical component <u>(y)² = (-) a (x-h)² + k</u>

cause  the parabola is horizontal and it opens on the left.

          2. In the second parabola the vertex opens on the right and hence the      equation cane be given as,

    in vertical component <u>(y)² = a (x-h)² + k</u>

cause the parabola is horizontal and opens on the right.

       3. the third equation is given as,

        in horizontal component<u> (x²) =</u> <u> (-) a (x-h)² + k</u>

since the parabola is vertical and opens down.

        4. the fourth equation is given as,

        in the horizontal component  <u>(x)² = a (x-h)² + k</u>

since the parabola is vertical and opens up.

             

   

7 0
2 years ago
An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.
Greeley [361]

Answer: 1) 0.6561    2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

P(X=x)=^nC_xp^x(1-p)^{n-x}

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel.  : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}

=(1)(0.90)^4=0.6561

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0
3 years ago
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