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exis [7]
3 years ago
14

Okay, third times the charm.

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Answer:

100% = $405,500

100 + 24 = 124%

124/100=1.24

$405,500 x 1.24^18 = $19479651.89

$19479651.89 - $405,500 = $19074151.89 profit.

To nearest whole number is $19074152.

Hope this helps!

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Kayla drives 15 miles in 20 minutes. If she drove one hour in total at the same rat how far did she go? Before you try that prob
alisha [4.7K]

Answer:

Kayla drove 45miles

5 0
3 years ago
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At a restaurant 12 ounces of ground beef is used to make 4 hamburger patties. The number of hamburger patties
NNADVOKAT [17]

Answer:

Its 3

Step-by-step explanation:

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3 years ago
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pedro has 6 packs of gum with p pieces in each pack he had a total of 72 pieces of gum decide whether each equation represents t
Serga [27]

Answer:

6p = 72 --- The equation

The solution is 12 packs i.e. p = 12

Step-by-step explanation:

No options given. So, I will solve generally.

Given

Packs = 6

Quantity = p per pack

Total = 72

Required

Determine the equation

This is calculated using:

Packs * Quantity = Total

6 * p = 72

6p = 72

Divide both sides by 6

p = 12

4 0
3 years ago
The following information was obtained from independent random samples taken of two populations. Assume normally distributed pop
Volgvan

Answer:

1. The 95% confidence interval for the difference between means is (-5.34, 11.34).

2. The standard error of (x-bar1)-(x-bar2) is 4.

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=10 has a mean of 45 and a standard deviation of √85=9.2195.

The sample 2, of size n2=12 has a mean of 42 and a standard deviation of √90=9.4868.

The difference between sample means is Md=3.

M_d=M_1-M_2=45-42=3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

The critical t-value for a 95% confidence interval is t=2.086.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.086 \cdot 4=8.34

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 3-8.34=-5.34\\\\UL=M_d+t \cdot s_{M_d} = 3+8.34=11.34

The 95% confidence interval for the difference between means is (-5.34, 11.34).

6 0
4 years ago
becky made batches of 8 muffins for a bake sale. She kept 3 muffins. Select three numbers that could be the number to the bake s
muminat

Answer:

A. 13; D. 29; F. 37

Step-by-step explanation:

Add 3 to each of the given numbers, then select the result that is divisible by 8.

The sums are 16, 22, 27, 32, 38, 40

Of those numbers, the ones divisible by 8 are 16, 32, 40. These correspond to choices A, D, F.

6 0
4 years ago
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