Answer:
Why do you talk with the other people so much???
Step-by-step explaWnation:
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
Answer: A is 70 B is 45 and C is 50
Step-by-step explanation:
Answer:
the first one on the bottom
Step-by-step explanation:
There is a little trick to find out if it is a function or not. This trick is called the vertical line test. if you can scan the figure with a virtual line and it does not touch more than one side of the figure at one time then it is a function. if it touches more than one side or line of the figure it is not a function.
Function A does not seem to be a linear equation so there is not a slope.
