Question

SOMEONE PLEASE HELP ANSWER MY QUESTIONS!!!!!!!!!!!!

Answer 1

1)
$y=mx+b$
where m is the slope

We know the slope is 5 and the line passes through the point (4,3).

$m=5 \\ (4,3) \\ x=4 \\ y=3 \\ \\ 3=5 \times 4 + b \\ 3=20 + b \\ b=3-20 \\ b=-17$

The equation of the line is:
$y=5m-17$

Now the second point:
$(2,y) \\ x=2 \\ y \\ \\ y=5 \times 2 -17 \\ y=10-17 \\ y=-7$

The answer:
The value of y is -7.

2)
The line passes through the origin, or the point (0,0), and has a slope of -32.
The slope is negative so the line goes down from left to right.
It crosses both x and y axes in the point (0,0).
Therefore, it only passes through II and IV quadrant.

You can also find the equation of the line, find one more point and draw it.
$y=mx+b \\ \\ m=-32 \\ (0,0) \\ x=0 \\ y=0 \\ \\ 0=-32 \times 0 + b \\ b=0 \\ \\ y=-32x$

Find the y-coordinate of the point for example (1,y).
$(1,y) \\ x=1 \\ y \\ \\ y=-32 \times 1 \\ y=-32$

The line passes through the points (0,0) and (1,-32). Now you can draw it (see the attachment).

The answer:
The line passes through quadrants II and IV.