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3 years ago

How do u solve 4(3x-1)=9-x

Mathematics

1 answer:

Nastasia [14]3 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

Well the first step is to apply the distributive property:

4(3x - 1) is equal to (12x - 4). You DISTRIBUTE a '4' to what is inside the parentheses.

And btw, to make it easier, you can make 9 - x so that x is first. For example, (-x + 9). They're both the same thing, just written differently.

Your new equation is 12x - 4 = -x + 9. You want to now solve the equation.

Add the (-x) to both sides. It cancels out on the right side and you add it to 12x on the left side.

[If there's no number in front of a variable, you can always just put 1 in order to make it easier]

12x + 1x = 13x. Your new equation is 13x - 4 = 9. This should look very familiar. You simply add 4 to both sides. 9 + 4 = 13

Finally, 13x = 13. Divide 13 ÷ 13 to get 1.

x = 1

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2x²-5x-12=0 (simplify solution set)

Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

$ax^2+bx+c=0$

Let's find a, b, c:

a is the coefficient of x^2
b is the coefficient of x
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Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}$

$x=\frac{5\pm\sqrt{121} }{4}$

$x=4$ or $x=\frac{-3}{2}$

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<u>Answer:</u>

x = 4 or x = -3/2

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