If A+B+C=180 Prove that Sin2A+Sin2B+Sin2C=4sinASinBSinC<br>

I think the answer is D because 73+62=135 and 180-135= 45 and angles 2 and 5 are alt. int. because of the backwards z shape.FYI, if u have a
backwards or forwards z or n, it is alt. int. in the angles that are INSIDE not outside.:)

6 0

3 years ago

How do you know 4/5 is already simpless? Explain

Tema [17]

Answer:

cause u cant make it more simpler

Step-by-step explanation:

4 and 5 cannot bbe cancelled by any number

6 0

3 years ago

Read 2 more answers

Write an explicit formula for the nth term or the sequence 8,-24, 72

miskamm [114]

Answer:

$T_n =-\frac{8}{3} (-3)^{n}$

Step-by-step explanation:

Given

$Sequence: 8, -24, 72$

Required

Determine the n term

The above sequence is geometric. So, we calculate the common ratio first:

$r = \frac{T_2}{T_1}$

$r = \frac{-24}{8}$

$r = -3$

The equation is then calculated using:

$T_n = ar^{n-1}$

Where

$a = T_1 = 8$

and

$r = -3$

The equation becomes:

$T_n =8 * (-3)^{n-1}$

Apply law of indices:

$T_n =8 * (-3)^{n} * (-3)^{-1}$

$T_n =8 * (-3)^{n} * \frac{1}{-3}$

$T_n =-8 * (-3)^{n} * \frac{1}{3}$

$T_n =-\frac{8}{3} * (-3)^{n}$

$T_n =-\frac{8}{3} (-3)^{n}$

5 0

3 years ago

Use the discriminant to describe the roots of each equation. Then select the best description.

Misha Larkins [42]

Answer:

see explanation

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 : a ≠ 0, then

The nature of it's roots can be determined by the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real and distinct

• If b² - 4ac = 0 then roots are real and equal

• If b² - 4ac < 0 then roots are not real

For x² - 4x + 4 = 0 ← in standard form

with a = 1, b = - 4, c = 4, then

b² - 4ac = (- 4)² - (4 × 1 × 4) = 16 - 16 = 0

Hence roots are real and equal

This can be shown by solving the equation

x² - 4x + 4 = 0

(x - 2)² = 0

(x - 2)(x - 2) = 0, hence

x - 2 = 0 or x - 2 = 0

x = 2 or x = 2 ← roots are real and equal

8 0

3 years ago

A professor gives two types of quizzes, objective and recall. He is planning to give at least 15

nadya68 [22]

Answer:

x₁ = 20 x₂ = 0

z (min) = 20

Step-by-step explanation:

According to the problem statement:

Let´s call

Objective quiz = x₁ Recall quiz = x₂

First constraint

Quantity of quizzes at least 15

x₁ + x₂ ≥ 15

Second constraint:

Preparation time at least 300 minutes, then

15*x₁ + 30*x₂ ≥ 300

Third constraint

Average score at least 85 points

7*x₁ + 5*x₂ ≥ 85

General constraint x₁ ≥ 0 x₂ ≥ 0

Objective function z is:

z = 1* x₁ + 1,5*x₂ to minimize

The model:

z = x₁ + 1,5x₂ to minimize

Subject to

x₁ + x₂ ≥ 15

15*x₁ + 30*x₂ ≥ 300

7*x₁ + 5*x₂ ≥ 85

Using Atozmax (online solver) we find

x₁ = 20 x₂ = 0

z (min) = 20

5 0

3 years ago

If A+B+C=180 Prove that Sin2A+Sin2B+Sin2C=4sinASinBSinC​

If A+B+C=180 Prove that Sin2A+Sin2B+Sin2C=4sinASinBSinC