Solve the system of equations.
1 answer:
2x + 3y = 13
–6x + 4y = 0
multiply the first equation by 3
6x +9y = 39
then add the 2nd equation to the first
6x +9y = 39
–6x + 4y = 0
-------------------
13y = 39
divide by 13
y =3
now take an equation and solve for x by substituting in y
2x +3y =13
2x +3(3) =13
2x+9 =13
subtract 9 from each side
2x =4
divide by 2
x=2
Answer (2,3)
Choice A
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