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Naddik [55]
4 years ago
13

Solve the system of equations.

Mathematics
1 answer:
Llana [10]4 years ago
4 0

2x + 3y = 13

–6x + 4y = 0

multiply the first equation by 3

6x +9y = 39

then add the 2nd equation to the first

6x +9y = 39

–6x + 4y = 0

-------------------

13y = 39

divide by 13

y =3

now take an equation and solve for x by substituting in y

2x +3y =13

2x +3(3) =13

2x+9 =13

subtract 9 from each side

2x =4

divide by 2

x=2

Answer (2,3)

Choice A

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Answer:

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Step-by-step explanation:

Let's write this as a fraction:

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One way in which this could be approached would be to interchange 'd' and '2:'

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