2 years ago

What is the answer for u

Mathematics

1 answer:

Mamont248 [21]2 years ago

7 0

Answer:

cbbbbbbbbbbbbbbb

Step-by-step explanation:

abc

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What are the solutions of the equation 6x2 + x-1=0 ?

Aleksandr [31]

Answer:

Options B and D

Step-by-step explanation:

6x² + x - 1 = 0

6x² + 3x - 2x - 1 = 0

3x(2x + 1) - 1(2x + 1) = 0

(3x - 1)(2x + 1)

x = 1/3 and -1/2

Options B and D

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1 year ago

What expression is equivalent to 24+30

worty [1.4K]

1) 2(30x-24)
60x-48
2) 3(20x-16)
60x-48
3) 4(15x-12)
60x-48
Simplify
60x-48
12(5x-4)
Answer: 12(5x-4)

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3 years ago

What is the probability of choosing a numbered card from a deck of cards? Type your answer as a fraction.

hichkok12 [17]

Answer:

36/52 or 9/13

Step-by-step explanation:

Ace-9 for all suits; Diamond, Hearts, Spades and Clubs

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2 years ago

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Elden [556K]

Answer:

what probortation?

Step-by-step explanation:

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2 years ago

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Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

2 years ago