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3 years ago

I need to know this answer asap

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

Answer:

Step-by-step explanation:

It is the only equation given with multiple exponents and terms

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Evaluate −b2−2bx2−x when x=−2.

Y_Kistochka [10]

The answer...... is 6x+2

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3 years ago

Identify the problem with the following study. An internet poll on a website asks people to indicate whether or not they have a

ratelena [41]

Answer:

B. VOLUNTARY RESPONSE

Step-by-step explanation:

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3 years ago

Write the following comparison as a ratio reduced to lowest terms.<br> 114 hours to 13 days

kicyunya [14]

The ratio of 114 hours to 13 days is 19:52.

<h3>How to calculate the ratio?</h3>

It should be noted that ratio is simply used to show the comparison between two things that are illustrated.

In this case, we want to calculate the ratio of 114 hours to 13 days. It should be noted that 24 hours make one day. Therefore, 13 days will be:

= 13 × 24 = 312 hours.

The ratio of 114 hours to 13 days will be:

= 114 / 312

= 19 / 52

The ratio is 19:52.

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1 year ago

Adele has 3 64-ounce cartons of orange juice and 3 48-ounce cans of apple juice. How much juice does she have altogether?

ale4655 [162]

I think if u add 364+348 you will get 712

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2 years ago

Read 2 more answers

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago