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Brut [27]
3 years ago
13

2. A man with type B blood mamies a woman with type A blood. Their first child has type o blood. The couple says this is

Biology
2 answers:
Arisa [49]3 years ago
6 0

Blood types:

AB +

AB -

A +

A -

B +

B -

O +

O -

It is possible to have a child with O blood despite the parents having different blood types.

While the man tested for B blood, he could have been a combination between type o and B whereas, the woman was a combination of type A and o. Since A/B are dominant, they would 'stand out' contrarily to o.

This means that their children could have AB or O blood.

loris [4]3 years ago
5 0

Answer:

This is possible, the rest of their family tree might have blood type O and it might have been past down in the generations to them and the sperm had blood type O

Edit: i just accidentally rated my own answer

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Slow cooling of magma produce
Alex73 [517]

Answer:

The magma cools very slowly. As magma cools minerals are formed into an interlocking arrangement producing an igneous rock. As magma cools it undergoes reactions that form minerals. The rate of cooling is very important.

Explanation:

hope this helps

8 0
2 years ago
Most deer mouse populations inhabit regions with dark soils. These deer mice have dark brown fur. Populations of deer mice found
mixas84 [53]

Answer:

Tan fur helps the mice protect themselves from predators

Explanation:

The entrenchment of this phenotype in the population is powered by natural selection pressures. The mice with fur color that enable them to camouflage with their environment are predated less than mice with other fur colors. These tan mice are therefore more likely to survive and pass their genes to the next generation. Through successive generations, the allelic frequency for the tan fur color increases until it is the dominant allele in the population.

7 0
3 years ago
1) Glycogen phosphorylase catalyzes the removal of glucose from glycogen. The ∆G°’ for this reaction is 3.1 kJ/mole 1. Calculate
Andru [333]

Answer:

1. G° = -RT ln (G1P/P)

3.1 = 8.314 × 310 × ln (G1P/P)

3.1 / 2577.34 = ln (G1P/P)

0.0012 = ln (G1P/P)

0.0012 = (log G1P/P)/log 2.71828

0.4342 × 0.0012 = log G1P/P

0.00052 = log G1P/P

G1P/P = 10^0.00052 = 1.0012

P/G1P = 1/1.0012 = 0.9988

2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.  

Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.  

3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.  

4 0
3 years ago
Please help asap! ppllleeaasse and thank you!
Mashcka [7]
A is the correct answer I belive 

8 0
3 years ago
Read 2 more answers
List two reasons that enzymes are needed... why don't active<br> sitesexist on their own?
Yakvenalex [24]

Answer:

Enzymes are proteins in composition which are a very essential component of the metabolic reactions in the living organisms.

The properties of enzymes allow the enzymes to be used as a reaction catalyst which increases the speed of the reaction.

The enzymes lower the threshold energy of the chemical reaction and thus increases the rate of reaction.

The enzyme catalyses very complex reactions like a breakdown of complex biomolecules as well as the formation of complex biomolecules.

The active sites are present on the enzymes which bind the substrate molecule and increases the pace of reaction.

5 0
3 years ago
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