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vivado [14]
3 years ago
12

Which Trigonometric ratio (​Sin, Cos, ​or​ Tan​) would you need to use for the right triangle below?? ​How do you know?

Mathematics
2 answers:
OleMash [197]3 years ago
7 0
The answer is sin because x is opposite of the angle and you have the hypotenuse.
Lana71 [14]3 years ago
7 0

Answer:

Q1/ TAN

Q2/ TAN

Step-by-step explanation:

This is the formula for finding the length of a side (H).

tan30°=O/A=x/42

H=hypotenuse

O=opposite

A=adjacent

You might be interested in
find the equation of a line through the coordinate (3,6) and parallel to the line represented by y=5/3 x-1
maw [93]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0 or (0,y))


For lines to be parallel, their slopes have to be the SAME.


The given line's slope is 5/3, so the parallel line's slope is also 5/3

y = 5/3x + b

To find "b", plug in the point (3,6) into the equation

y = 5/3x + b

6 = 5/3(3) + b

6 = 5 + b

1 = b


y = 5/3x + 1

5 0
3 years ago
Two boys searching for buried treasure are standing underneath the same tree. one boy walks 12 m east and then 12 m north. the o
mylen [45]
Let
 The origin of coordinates the tree
 r1 = vector position of the child 1.
 r2 = vector position of the child 2
 Child 1:
 r1 = (12i + 12j)
 Child 2:
 r2 = (-18i + 11j)
 The scalar product will be given by:
 r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
 The scalar product of their net displacements from the tree is -84m ^ 2
5 0
3 years ago
Tell whether the blue figure is a reflection of the red figure.
valina [46]

Answer: Yes it is a reflection

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A hemisphere has an area of 256 pi cm^2. What is its volume?
Amanda [17]
\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\

\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}
7 0
3 years ago
Please help me I need to get this done by today
kifflom [539]

Answer:

Third quadrant

Step-by-step explanation:

Look at the attached image. All the points are in the third quadrant.

8 0
3 years ago
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