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AlladinOne [14]
3 years ago
8

PLEASE HELP ASAP FOR 15 POINTS There are white, blue, and red boats in a marina. Two-thirds of the boats in the marina are white

, 4/ 7 of the remaining boats are blue, and the rest are red. If there are 15 red boats, how many boats are in the marina? 15 POINTS!
Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

white 2/3

blue: 4/7 * (1 - 2/3) = 4/21

red: 1 - 2/3 - 4/21 = 1/7

15 / (1/7) = 105 boats are in the marina.


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kakasveta [241]

Answer:

The answer to your question is:   y = -47x + 661

Step-by-step explanation:

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m = - 47         I wasn't sure if the slope was -47 or -4.

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Formula

(y - y1) = m(x - x1)

Process

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                   y = -47x + 658 + 3

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(15,0)

Step-by-step explanation:

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3 years ago
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e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

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\int (pq')=pq-\int qp'

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and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

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notice how all the constants were combined into one big constant C.

7 0
3 years ago
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Lets start from 1:

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As you can see, 4 x 4 is 16. To make sure I'm correct, remember that a square roots consists two identical factors.

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mafiozo [28]

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3 0
1 year ago
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