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Wewaii [24]
3 years ago
8

Try to fill in the missing numbers

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0

9514 1404 393

Answer:

  [[274][895][136]]

Step-by-step explanation:

Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.

The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.

There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.

The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.

Our solution is ...

row 1: 2 + 7 × 4 = 30

row 2: 8 + 9 × 5 = 53

row 3: 1 × 3 - 6 = -3

And that makes the column equations be ...

col 1: 2 - 8 + 1 = -5

col 2: 7 + 9 / 3 = 10

col 3: 4 × 5 - 6 = 14

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Step-by-step explanation:

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A farmer has three silos. The largest silo has a diameter of 24 feet. The radius of the smallest silo is one-thrid as big as the
aivan3 [116]

Answer:

Exact:

16 \pi~ft;~~20 \pi~ft;~~24 \pi~ft

Approximate:

50.3 ft, 62.8 ft, 75.4 ft

Step-by-step explanation:

Let's find the radius of each silo using the given information.

<em>"The largest silo has a diameter of 24 feet."</em>

d_{largest} = 24~ft

r_{largest} = \dfrac{d_{largest}}{2} = \dfrac{24~ft}{2} = 12~ft

<em>"The radius of the smallest silo is one-third as big as the diameter of the largest."</em>

r_{smallest} = \dfrac{24~ft}{3} = 8~ft

<em>"The middle-sized silo has a radius that is 2 feet greater than the radius of the smallest silo."</em>

r_{middle} = r_{smallest} + 2~ft = 8~ft + 2~ft = 10~ft

The three radii are: 8 ft, 10 ft, and 12 ft.

Now we use the circumference formula with each radius to find the circumferences.

Smallest:

C = 2 \pi r = 2 \times \pi \times 8~ft = 16 \pi~ft

Middle:

C = 2 \pi r = 2 \times \pi \times 10~ft = 20 \pi~ft

Largest:

C = 2 \pi r = 2 \times \pi \times 12~ft = 24 \pi~ft

The circumferences above are exact. If you want approximations, then use a calculator and an approximation for pi.

The circumferences are approximately: 50.3 ft, 62.8 ft, 75.4 ft

4 0
3 years ago
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