Ask question

Ask question

All categories

3 years ago

6

determine the equation of the straight line which passes through the point 1 and 5 and is perpendicular to the line 3x + y is eq

ual to 4

1 answer:

xenn [34]3 years ago

7 0

The straight line is perpendicular to y = -3x + 4.

Therefore, the gradient of the straight line must be 3.

The equation of the straight line is y = 3x + 2.

You might be interested in

Are 45/75 and 90/150 proportional?

lesya [120]

Yes they are
. 90/150= 3/5
so 45/75 and 3/5.

3 0

3 years ago

Read 2 more answers

Find the correct answer.

Ksenya-84 [330]

Answer:

-0.2?

Step-by-step explanation:

Just solve the equation.

8 0

3 years ago

there are 30 students in mr. Holland music class. If 30% of the students play in the school band, how many students in the class

MA_775_DIABLO [31]

9 students 30% ends up being .3%, multiply .3% by 30 students which equals 9.

3 0

3 years ago

Read 2 more answers

How to solve a mixed number fraction

lesantik [10]

You find a common denominator (the bottom one) and then add the numerator (the top) but you don't add the denominator, you just make it the same

8 0

3 years ago

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago