Answer:
(21 + 11)2 = 64
So, I don't think teachers do this, but this is my way of doing it
Okay, so first, I divided 64 by 2 :
64 ÷ 2 = 32
Then, I subtracted 11 from 32:
21
Now, to check, just do the problem :
(21 + 11)2 = 64
32 * 2 = 64
B. 12 would be your answer
Too much work!!!!!!!!!!!!
Answer:
2) Equation 1 and Equation 2 have the same number of solutions.
Step-by-step explanation:
The two given equations are
1) 15x + 6 = 41 and 2) 2x + 13 = 28
Solving both equations, we get
Solving (1) : 15x + 6 = 41 ⇒ 15x = 41 - 6 = 35
or, x = 35/15 ⇒ x = 7/3
Solving (2) : 2x + 13 = 28⇒ 2x = 28 - 13 = 15
or, x = 15/2 ⇒ x = 15/2
So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.
#1) (b)
#2) (d)
#3) (d)
My explanations are the same as your previous questions.
