Answer:
X and Y are two viable points when plotting a line. These points also happen to tell us where the line is when x and y equal zero.
Step-by-step explanation:
<h2>
The required "option A) 
" is correct.</h2>
Step-by-step explanation:
We have,
..... (1)
To find, 
= ?
Differentiating equation (1) w.r.t. 'x', we get
![\dfrac{dy}{dx}= \dfrac{d[(3x + x^2)^5]}{dx}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%20%5Cdfrac%7Bd%5B%283x%20%2B%20x%5E2%29%5E5%5D%7D%7Bdx%7D)
⇒ 
[ ∵ 
⇒ 
]
⇒ 
⇒ 
Thus, the required "option A) " is correct.
The answer is: " 4.58 * 10⁻² " .
_____________________________________________________
Answer:
C. -1/2
Step-by-step explanation:
(-2,2)
(0,1)
(2,0)
Change in y = -1
Change in x = 2
Equation: y = -1/2x + 1
Leg 1 would be 120 ft, leg 2 would be 50 ft. use the formula a^2+b^2=c^2, a&b are legs, c is hypotenuse. sqt 16900= 130. (the issue with the question is the height of the person, but I think the question wants the hypotenuse.
