Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
Answer:
Step-by-step explanation:
Here's the thing. It is easier to figure out the probability of not getting a six even once during the 50 rolls.
The chance of that happening is (5/6)^50 = 0.00010988
So the probability is succeeding is (1 - 0.00010988) = 0.9999 rounded to 4 places.
32,767/32,768 is in lowest terms and can't be reduced.
Apperently someone deleted my question i was trying to see if you had understood what i was trying to help you on
Out of 6 wedges, Jody eats 4 wedges obviously so he eats 4/6 of the orange or to make it simple 2/3 of it
