3 years ago

12.50 for 5 ounces unit rate

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

12.50 / 5 = 2.50 per ounce

TEA [102]3 years ago

6 0

Divide 5 into 12.50 and you should get 2.5. So it'll will be 2.5 per ounce

You might be interested in

Write the following equations in slope intercept form

Rus_ich [418]

Answer:

problem 1 2x+5y= 0

×=-1/2-5/2y

problem 2 y=1 3/7y y=-1.428571

7y=-10

problem 3 x=-7

problem 4 x-y=20

x=-20

7 0

3 years ago

3/9 + 3/9 = ??????????????

blsea [12.9K]

3/9 + 3/9 = 6/9

We know that 6/9 can still be simplifed.

So 6/9 will be divided by three.

= 2/3 is the answer.

8 0

3 years ago

Read 2 more answers

Radius is 6 height is 4 what is the volume rounded to the nearest hundredth

Ainat [17]

Answer:

Step-by-step explanation:

What are we calculating ??? If it is volume of a cone=1/3πr^2h

1/3×3.142×4×4×6

=100.54units cube

To calculate volume of cylinder=πr^2h

V=3.142×4×4×6

V=301.63 units cube

6 0

3 years ago

A group of farmers planted 62 fields of vegetables. of the fields they planted, 4/5 were planted with cabbage. how many fields o

chubhunter [2.5K]

Total number of fields of vegetables = 62

Thus,

The amount of fields that is cabbage = $\frac{4}{5} * 62 = \frac{248 }{5} = 49.8$

4 0

3 years ago

1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the

Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

$\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I$

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

$f(x)=e^{3x}+\cos(5x),$

$g(x)=e^{3x}-\cos(5x),$

$h(x)=\cos(5x).$

Then, letting α = 1, β= -1 and ω = -2, we see that:

$\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.$

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0

3 years ago