Area of a square = Side × Side
Side = 7x-3
Area of the square = (7x-3) × (7x-3)
= 7x(7x-3) -3(7x-3)
= 49x^2 -21x -21x +9
=49x^2 -42x +9
Answer:
The answer to your question is y = 4/3x + 1/3
Step-by-step explanation:
Data
Point A = (2, 3)
Point B = (5, 7)
Process
1.- Calculate the slope
x1 = 2 y1 = 3
x2 = 5 y2 = 7
m = (y2 - y1)/(x2 - x1)
- Substitution
m = (7 - 3)/(5 - 2)
- Slope
m = 4/3
2.- Find the equation of the line
y - y1 = m(x - x1)
y - 3 = 4/3(x - 2)
y - 3 = 4/3x - 8/3
y = 4/3x - 8/3 + 3
y = 4/3x - 8/3 + 9/3
y = 4/3x + 1/3
1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
