Xy=6
x=6/y......1
3x+2y=12
from1
3*(6/y)+2y=12
{after solving}2y^2-12y+18=0
y^2-6y+9=0 {taking y common}
y^2-3y-3y+9=0
y(y-3)-3(y-3)=0
y=3,3............2
putting 2 in 1
x=2.........3
9x^2+4y^2=
from 2 and 3
9*4+4*9=36+36=72
Answer:
Loaves of bread: b can't be a negative value, then the first table doesn't include viable solutions.
The number of loaves of bread must be a whole number, then the second table doesn't include viable solutions.
c=3.5b
if b=0→c=3.5(0)→c=0
If b=3→c=3.5(3)→c=10.5
If b=6→c=3.5(6)→c=21
If b=9→c=3.5(9)→c=31.5
The third table includes viable solutions
Answer:
The solution would be (-4, -2)
Step-by-step explanation:
To find this simply add the two equations together.
-9x+7y=22
9x-5y=-26
----------------
2y = -4
y = -2
Now we have the y value, we can solve for the x value.
9x-5y=-26
9x-5(-2)=-26
9x+10=-16
9x=-36
x = -4
You’re answer is B, you just have to multiply all of the sides together and then add your sums.
Hope this helps:)
Answer:
Your solution is y = -27
Step-by-step explanation:
The image below shows the steps. (Mark brainliest if this helps please! ) :)
