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vitfil [10]
3 years ago
11

On a coordinate plane, polygon GHIJ translates 8 units to the left to form polygon G'H'I'J'. Which of the following equations is

not necessarily true? GH = G'H' G'G = 8 units m∠HIJ = m∠H'I'J' m∠HI'J = m∠H'IJ'
Mathematics
2 answers:
devlian [24]3 years ago
5 0
We know that
<span>When you translate a figure, none of the lengths change and none of the angles change
</span>
therefore

the answer is
G'G = 8 units ------> <span>is not necessarily true

</span>
alexandr1967 [171]3 years ago
4 0

Answer:

G'G = 8 units

Step-by-step explanation:

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-10/5+2(7-9)^2
Oksana_A [137]
Answer: -4

Reasoning: so first you need to subtract the 7 from the 9 to get -2. Then you square it to get 4 because a negative 2 times -2 is 4. Then you multiply the 4 by the 2 to get 8. You can simplify the -10/5 to -1/2 and multiply that by the 8 to get -8/2 which simplified out to -4.


I hope that helps.
8 0
3 years ago
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To start, which measurement does Tommy need to
Luba_88 [7]

Answer:

C. volume

Step-by-step explanation:

when youre starting your measurements you want to start the volume first.

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3 years ago
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What is the image of the point (-9,-1) after a rotation of 270 degrees counterclockwise about the origin?
Hunter-Best [27]

Answer:

(-1,9)

Step-by-step explanation:

coortinate point is (-9,-1)

use formula

(x,y)=(y,-x)

(-9,-1)=(-1,9)

3 0
3 years ago
Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all
Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function  f(x) = x3 – 5x2 + 6x . Graph of this function is given below  . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the  value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 0^3- 5(0)^2 + 6(0)

⇒ f(0) =0

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 2^3- 5(2)^2 + 6(2)

⇒ f(0) =0

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ f(x) = x^3- 5x^2 + 6x

⇒ f(0) = 3^3- 5(3)^2 + 6(3)

⇒ f(0) =0

Therefore , the solutions to the related equation are 0,2,3 .

3 0
3 years ago
If 3/x=5/y then what is the value of y/x?<br> plss help
netineya [11]

Answer:

Step-by-step explanation:

3/x=5/y

3y/x=5

y/x=5/3

7 0
3 years ago
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