Answer:
There are no examples provided here, but synthesis is when two substances combine to form one! This could be shown in an chemical equation.
Explanation:
Answer:
La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.
Explanation:
Answer:
The main competing reaction when a primary alkyl halide is treated with alcoholic potassium hydroxide is SN2 substitution.
Explanation:
The relative percentage of products of the reaction between an alkyl halide and alcoholic potassium hydroxide generally depends on the structure of the primary alkylhalide. The attacking nucleophile/base in this reaction is the alkoxide ion. Substitution by SN2 mechanism is a major competing reaction in the elimination reaction intended.
A more branched alkyl halide will yield an alkene product due to steric hindrance, similarly, a good nucleophile such as the alkoxide ion may favour SN2 substitution over the intended elimination (E2) reaction.
Both SN2 and E2 are concerted reaction mechanisms. They do not depend on the formation of a carbocation intermediate. Primary alkyl halides generally experience less steric hindrance in the transition state and do not form stable carbocations hence they cannot undergo E1 or SN1 reactions.
SN2 substitution cannot occur in a tertiary alkyl halides because the stability of tertiary carbocations favours the formation of a carbocation intermediate. The formation of this carbocation intermediate will lead to an SN1 or E1 mechanism. SN2 reactions is never observed for a tertiary alkyl halide due to steric crowding of the transition state. Also, with strong bases such as the alkoxide ion, elimination becomes the main reaction of tertiary alkyl halides.
Rdaioactive decay results in the formation of a different element. Plutonium decays by emitting alpha emission to form uranium. Thermal energy is emitted as the alpha particles are absorbed and the kinetic energy is converted to heat. The amount of energy is computed by the formula;
E = mc²
E = 0.000046 × (3 ×10^8)
Energy = 4.14 ×10^13 Joules
Answer:
a. Propanol
b. Propanone
c. Butanal
Explanation:
From the given information:
We are to state which of the given samples are more soluble in water.
The solubility of an organic molecule in water depends on the polarity of the given organic molecule. This solubility behaviour conforms with the general rule -"like dissolve like". Solubility is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature. Water is a polar solvent; therefore, an organic molecule that will also dissolve in water must be polar.
From the first pair, we have propane and propanol.
Propanol is more soluble in water than propane due to its polarity in water.
From the second pair:
Propanone is an alkanone (ketone group) with three carbon chain directly bonded to an oxygen double bond. At the same time, 3-hexanone has six carbon chain ketone group with the oxygen double bond located at the third carbon chain ( a hydrophobic "water-fearing" compound). Thus, the shorter the carbon chain, the more polar the organic molecule is and the more it is likely going to dissolve in water. Therefore, Propanone is more soluble in water than 3-hexanone.
From the third pair: The shorter the carbon chain, the more soluble in water it will become.
Butanal is the fourth element on the alkanal family group while hexanal is the sixth compound in the alkanal family group. As such, butanal is more soluble in water than hexanal.