Answer:
7.7 mol/L or M
Explanation:
Molarity is defined as moles of solute over litres of solution. So, in essence, Molarity= moles/litres
or often written as M=mol/L
Here we have 9.5 moles of HCl, and 1.24L of water so we just plug those in equation...
M= 9.5/1.24 = 7.7 mol/L or M
Answer:
12 moles H
2
O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
In your case, the balanced chemical equation for this synthesis reaction looks like this
2
H
2(g]
+
O
2(g]
→
2
H
2
O
(l]]
Notice that the reaction requires
2
moles of hydrogen gas and
1
mole of oxygen gas to produce
2
moles of water.
This tells you that the reaction produces twice as many moles of water as you have moles of oxygen gas that take part in the reaction.
You know that your reaction uses
6.0
moles of oxygen. Assuming that hydrogen gas is not a limiting reagent, you can say that the reaction will produce
6.0
moles O
2
⋅
2
moles H
2
O
1
moles O
2
=
12 moles H
2
O
Explanation:
Answer:
191.6 g of CaCl₂.
Explanation:
What is given?
Mass of HCl = 125.9 g.
Molar mass of CaCl₂ = 110.8 g/mol.
Molar mass of HCl = 36.4 g/mol.
Step-by-step solution:
First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:
Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:
Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:
The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:
The answer would be that we're producing a mass of 191.6 g of CaCl₂.
Answer:
Mole fraction of solute (heptane) → 0.73
Explanation:
Mole fraction = Moles of solute or solvent / Total moles
Let's calculate the moles of everything:
Moles of solute → Mass of solute / Molar mass
36 g / 100 g/mol = 0.36 moles
Moles of solvent → Mass of solvent / Molar mass
16 g / 119.35 g/mol = 0.134 moles
Total moles = 0.36 + 0.134 = 0.494 moles
Mole fraction of solute = 0.36 / 0.494 → 0.73
The balanced chemical reaction is written as:
<span>Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g)
</span>
We are given the amount of the reactant zinc to be used in the reaction This amount would be the starting point for the calculation. It is as follows:
5.00 mol Zn ( 1 mol H2 / 1 mol Zn ) (2.02 g H2 / 1 mol H2 ) = 10.1 g H2
Therefore, the correct answer is the second option.
