Answer:
the boiling of 10g of liquid water
Answer:
Air is mostly gas
The air in Earth's atmosphere is made up of approximately 78 percent nitrogen and 21 percent oxygen. Air also has small amounts of lots of other gases, too, such as carbon dioxide, neon, and hydrogen.
Explanation:
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Answer:
<h2>326,250 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>326,250 J</h3>
Hope this helps you
Answer: E
=
1.55
⋅
10
−
19
J
Explanation:
The energy transition will be equal to 1.55
⋅
10
−
1
J
.
So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition
1
λ =
R
⋅
(
1
n
2
final −
1
n
2
initial )
, where
λ
- the wavelength of the emitted photon;
R
- Rydberg's constant - 1.0974
⋅
10
7
m
−
1
;
n
final
- the final energy level - in your case equal to 3;
n
initial
- the initial energy level - in your case equal to 5.
So, you've got all you need to solve for λ
, so
1
λ =
1.0974
⋅10 7
m
−
1
⋅
(....
−152
)
1
λ
=
0.07804
⋅
10
7
m
−
1
⇒
λ
=
1.28
⋅
10
−
6
m
Since
E
=
h
c
λ
, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by
h
⋅
c
, where
h
- Planck's constant -
6.626
⋅
10
−
34
J
⋅
s
c
- the speed of light -
299,792,458 m/s
So, the transition energy for your particular transition (which is part of the Paschen Series) is
E
=
6.626
⋅
10
−
34
J
⋅
s
⋅
299,792,458
m/s
1.28
⋅
10
−
6
m
E
=
1.55
⋅
10
−
19
J
Answer:
The answer to your question is below
Explanation:
1.-
a) Look for the mass number of Gold in the periodic table
Mass number = 197 g
Use proportions to answer this question
197 g of gold ------------- 6.023 x 10 ²³ atoms
4.64 g of gold ---------- x
x = (4.64 x 6.023 x 10²³) / 197
x = 1.42 x 10²² atoms
2.- mass of 4.12 x 10²⁴ molecules of glucose
Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)
= 72 + 12 + 96
= 180 g
180 g of glucose ------------------- 6.023 x 10 ²³ molecules
x ------------------- 4.12 x 10 ²⁴ molecules
x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³
x = 1231.3 g of glucose
