All categories

2 years ago

Probability!

Mathematics

1 answer:

Reil [10]2 years ago

7 0

Answer:

26/31

Step-by-step explanation:

N(B)=12

N(G)=14

N(Y)=5

N(S)=N(B)+N(G)+N(Y)

=12+14+5

=31

Now,

P(Not getting yellow)=N(B)+N(G)/N(S)

=12+14/31

=26/31

You might be interested in

Help what do I do do i just write y-3x+5 or solve it

Rina8888 [55]

Answer:

y=-3x+5

Step-by-step explanation: Yes you have it correct. The question is asking for you to put it into an equation that fits the slope and y-intercept which is slope-intercept form. Additional note, when you have a problem like this and it doesn't say what type of equation form to put it in, put it in slope-intercept form for simplicity's sake.

3 0

1 year ago

Read 2 more answers

Classify the system correctly <br> Y = 5x +2<br> 10x - 2y = 12

s344n2d4d5 [400]

Answer:

It's a simultaneous equation because it as two solution

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$